Twin graphs?

Getting ( d=v2t+1/2at² ) Equation Number 3 from a v-t graph
 you need the 2 main equations. the "mother" and the "father"
The area of the Triangle can be calculated using -----> d=1/2(v2-v1)t 
                       Rectangle can be calculated using ---> d=v2t


Combine the two ---> d=v2t + 1/2t (v1 - v2)t <-------- (-_-)
 
a=(v2-v1) / t or at=V2-v1 <--------- (^_^)

                                             Sub (^_^) into (-_-) to form 

                                             d=1/2t(v2-v1)+v2t

                                               =1/2t(at)+v2t

                                               =v2t + 1/2at²

 

 

 

The area of the Triangle can be 

                                calculated using -----> d=1/2(v2-v1)t 

Large Rectangle can be calculated using ---> d=v2t

Therefore the imagery triangle minus the large Rectangle 

 

        d=V1t-1/2t(v2-v1)

         =V1t-1/2t(at)

                                                                     =v1t - 1/2at²